Check a Number for an Armstrong Number

Program:


    #include<iostream.h>
    #include<conio.h>
void main() { int num,n,sum,r; clrscr(); cout<<"\nEnter the number: \n"; cin>>num; n=num; sum=0; while(n!=0) { r=n%10; sum+=(r*r*r); n/=10; } if(sum==num) cout<<num<<" is an Armstrong number"; else cout<<num<<" is not an Armstrong number"; getch(); }
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